Question
How many seconds will a train 66 m in length, travelling
at the rate of 40 km an hour, take to pass another train 82 m long, proceeding in the same direction at the rate of 28 km an hour?Solution
Relative speed = 40 – 28 = 12 km/hr Speed (m/sec) = 12 × (5/18) = 10/3 m/sec Time = Total length of both the trains/Relative speed => Time = (82 + 66)/(10/3) = 44.4 sec
An unexpected piece of good fortune Â
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