Question
How many seconds will a train 66 m in length, travelling
at the rate of 40 km an hour, take to pass another train 82 m long, proceeding in the same direction at the rate of 28 km an hour?Solution
Relative speed = 40 – 28 = 12 km/hr Speed (m/sec) = 12 × (5/18) = 10/3 m/sec Time = Total length of both the trains/Relative speed => Time = (82 + 66)/(10/3) = 44.4 sec
7(1/7)% of 3500 + 6(2/3)Â % of 6000 = ? + 552.5
What value should come in the place of (?) in the following questions.
336 ÷ 6 ÷ √16 * ? = 1400 ÷ 4
What will come in the place of question mark (?) in the given expression?
(18 × 8 + 24) × 4 = ?
Simplify the following expression:
  (400 +175) ² - (400 – 175) ² / (400 × 175)
√(24²+285-8²-172) = ?²
26 X √25 + 15 - 80% of 120 = ?2Â
? = (22% of 25% of 60% of 3000) + 21

√? = 120 - 102 + ∛125