Question
Train ‘X’ is 360 metres long and takes 18 seconds to
cross a pole. Speed of train ‘Y’ is 22 m/sec. If both trains cross each other in 16 seconds while travelling towards each other, then what is the length of train ‘Y’?Solution
ATQ,
Speed of train ‘X’ = (360/18) = 20 m/sec
So, relative speed of train ‘X’ with respect to train ‘Y’ (travelling towards each other) = 20 + 22 = 42 m/sec
Let the length of train ‘Y’ = ‘x’ metres
Distance covered by both trains together in 16 seconds = (360 + x) metres
Or, 16 × 42 = 360 + x
Or, 672 = 360 + x
Or, x = 672 – 360 = 312
So, length of train ‘Y’ = 312 metres
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