Question
The lengths of trains 'P' and 'Q' are 180 metres and 120
metres respectively. Train 'P' crosses a platform 'Y' of 240 metres in 24 seconds. If 'P' and 'Q' cross each other while moving in opposite directions in 12 seconds, then find the time taken by 'Q' to cross the platform 'Y'.Solution
ATQ,
Let the speed of 'P' be 'x' m/sec So, total distance covered by 'P' while crossing the platform = (180 + 240) = 420 metres ATQ, 420 = x × 24 So, x = 17.5 m/sec Let the speed of 'Q' be 'y' m/sec Relative speed of 'P' with respect to 'Q' = (x + y) = (17.5 + y) m/sec Total distance = 180 + 120 = 300 metres ATQ, 300 = (17.5 + y) × 12 => 17.5 + y = 25 => y = 25 - 17.5 = 7.5 m/sec So, time taken by 'Q' to cross the platform = (120 + 240) ÷ 7.5 = 360 ÷ 7.5 = 48 seconds
15.232 + 19.98% of 539.99 = ? × 8.99
647.1 ÷ ? + 72.3 × 209.81 – 8743.1 = 6404
(1560.23 ÷ 25.98) + (768.32 ÷ 23.9) + 1814.11 = ?
A train takes 8 seconds to pass a dog running in the opposite direction to the train at a speed of 10 m/s. Given that the train i...
? + 154.99 – 110.01 = 30.01 × 4.98
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(3.21) ? + 37.92 ÷ 1.98 = (5.99 + 3.99) 2
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
1459.98 ÷ 40.48 × 12.12 = ? × 3.16
What is the smallest integer that should be subtracted from 653 to make it divisible by both 23 and 27?
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