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Let the length of the train = ‘L’ metres Distance covered by the train in 24 seconds = ‘L’ metres Distance covered by the train in 34 seconds = (L + 300) metres So, distance covered by the train in (34 – 24) seconds = L + 300 – L = 300 metres So, speed of the train = (300 / 10) = 30 m/s So, length of the train = 30 × 24 = 720 metres Relative speed of the motorbike with respect to the train = 60 − 30 = 30 m/s So, time taken by the motorbike to cross the train = (720 / 30) = 24 seconds
? = (√784 - √361) + 102 - 3√512
54% of 250 = 6 × 21 + √?
40.5 ÷ [4/5 of (32 + 18) - 29/2] = ? ÷ 102
6% of 520 + 5% of 620 = ?
15.50% of 6240 – 426.31 = ?
400 % of 20 + 65 % of 620 - 92 × 5 = ?
{(5/8) + (4/5)} × (?/19) = 33
√196 + (0.25 × 144) + 19 = ? + 72
{5% of (20 × 25) + 6% of (30 ×35)} ÷ 11 = ?