Question
Train ‘A’ travelling with a speed of 80 km/h can
cross a pole in 9 seconds. If the length of train ‘B’ is 20% less than that of train ‘A’ and it can cross a pole in 16 seconds then speed (in km/h) of train ‘B’ is:Solution
Speed of train ‘A’ = 80 × (5/18) = (200/9) m/s Length of train ‘A’ = (200/9) × 9 = 200 metres Length of train ‘B’ = 0.8 × 200 = 160 metres Speed of train ‘B’ = (160/18) × (18/5) = 32 km/h
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