Question
Train βAβ travelling with a speed of 42 km/h can
cross a pole in 6 seconds. If the length of train βBβ is 10% less than that of train βAβ and it can cross a pole in 9 seconds then speed (in km/h) of train βBβ is:Solution
Speed of train βAβ = 42 Γ (5/18) = (35/3) m/s Length of train βAβ = (35/3) Γ 6 = 70 metres Length of train βBβ = 0.9 Γ 70 = 63 metres Speed of train βBβ = (63/9) Γ (18/5) = 25.2 km/h
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