Question
Train ‘A’ travelling with a speed of 42 km/h can
cross a pole in 6 seconds. If the length of train ‘B’ is 10% less than that of train ‘A’ and it can cross a pole in 9 seconds then speed (in km/h) of train ‘B’ is:Solution
Speed of train ‘A’ = 42 × (5/18) = (35/3) m/s Length of train ‘A’ = (35/3) × 6 = 70 metres Length of train ‘B’ = 0.9 × 70 = 63 metres Speed of train ‘B’ = (63/9) × (18/5) = 25.2 km/h
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