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Speed of train = (Length of train + Length of Platform)/Required time Length of train = 240 m Crossing time of platform = 3 × 60 = 180 sec Length of platform = 240 × 2 = 480 m Let the speed of train be x. Speed of train = (240 + 480)/180 ⇒  x = 4 m/s
l. p2Â - 3p - 54 = 0
II. q2Â - 19q + 90 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 6x² - 24x + 18 = 0
Equation 2: 5y² - 20y + 15 = 0
I. x2-2x- √5x+2√5 = 0
II. y2-√3 y- √2 y+ √6 = 0
...I. 3x2 – 16x + 21 = 0
II. y2 – 13y + 42 = 0
I. 63x2+ 148x + 77 = 0
II. 21y2+ 89y + 88 = 0
I. x² + 11x + 24 = 0
II. y² + 17y + 72 = 0
I. 99x² + 161 x + 26 = 0
II. 26 y² + 161 y + 99 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 45x + 450 = 0
Equation 2: y² - 48y + 540 = 0Â...
I. 2y² - 3y – 14 = 0
II. 3x² - 7x + 4 = 0
