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      Question

      A train of length 420 m can cross a platform of length

      ‘y’ m in 30 seconds. Also, it can cross another train of same length as that of the platform, moving at a speed of 22 m/sec in opposite direction, in 15 seconds. Find the value of ‘y’.
      A 160 m Correct Answer Incorrect Answer
      B 528 m Correct Answer Incorrect Answer
      C 328 m Correct Answer Incorrect Answer
      D 240 m Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let the speed of train be ‘s’ m/sec.

      According to question:

      (420 + y) = 30 × s -----(1)

      (420 + y) = 15 × (s + 22) -----(2)

      Solving (1) and (2), we get

      30 × s = 15 × (s + 22)

      30s – 15s = 15 × 22

      15s = 330

      s = 330 / 15

      s = 22 m/s

      Putting the value of ‘s’ in equation (1), we get

      (420 + y) = 30 × 22

      (420 + y) = 660

      y = 660 – 420

      y = 240 m

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