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    Question

    A train of length 420 m can cross a platform of length

    ‘y’ m in 30 seconds. Also, it can cross another train of same length as that of the platform, moving at a speed of 22 m/sec in opposite direction, in 15 seconds. Find the value of ‘y’.
    A 160 m Correct Answer Incorrect Answer
    B 528 m Correct Answer Incorrect Answer
    C 328 m Correct Answer Incorrect Answer
    D 240 m Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the speed of train be ‘s’ m/sec.

    According to question:

    (420 + y) = 30 × s -----(1)

    (420 + y) = 15 × (s + 22) -----(2)

    Solving (1) and (2), we get

    30 × s = 15 × (s + 22)

    30s – 15s = 15 × 22

    15s = 330

    s = 330 / 15

    s = 22 m/s

    Putting the value of ‘s’ in equation (1), we get

    (420 + y) = 30 × 22

    (420 + y) = 660

    y = 660 – 420

    y = 240 m

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