Question
Train βXβ is 360 metres long and takes 18 seconds to
pass a standing man. Speed of train βYβ is 25 m/sec. If both trains are moving towards each other and take 16 seconds to cross completely, what is the length of train βYβ?Solution
ATQ,
Speed of train βXβ = (360/18) = 20 m/sec So, relative speed of train βXβ with respect to train βYβ (moving towards each other) = 20 + 25 = 45 m/sec Let the length of train βYβ = βxβ metres Distance covered together in 16 seconds = (360 + x) metres Or, 16 Γ 45 = 360 + x Or, 720 = 360 + x Or, x = 720 β 360 = 360 So, length of train βYβ = 360 metres
500% of (121.8 + 16.4 β 28.2) = ? Γ 2
150% of 84 + ?% of 130 = 230
What will come in the place of question mark (?) in the given expression?
(72 Γ 4 β 92) Γ· 14 = ?
33 × ?2 – 6 × 5 = 3270
(3500 ÷ √1225) × √(20.25) = ? ÷ 4
What is 12% of 4% of 7% of 2 x 106 ?
Select the correct combination of mathematical signs that can sequentially replace the * signs and balance the given equation.
42 * 7 * 64 * 11 * 6 *4
Find the simplified value of the given expression:
7 of 9 Γ· 3 Γ 5Β² + β81 β 14What will come in the place of question mark (?) in the given expression?
(12.09)2 Γ 5.98 Γ· 26.95 = ? + 25Β
10% of 100 + 14 = ?% of 120