Question
Train ‘X’ is 360 metres long and takes 18 seconds to
pass a standing man. Speed of train ‘Y’ is 25 m/sec. If both trains are moving towards each other and take 16 seconds to cross completely, what is the length of train ‘Y’?Solution
ATQ,
Speed of train ‘X’ = (360/18) = 20 m/sec So, relative speed of train ‘X’ with respect to train ‘Y’ (moving towards each other) = 20 + 25 = 45 m/sec Let the length of train ‘Y’ = ‘x’ metres Distance covered together in 16 seconds = (360 + x) metres Or, 16 × 45 = 360 + x Or, 720 = 360 + x Or, x = 720 – 360 = 360 So, length of train ‘Y’ = 360 metres
20 ×33 + 12 × 23 - 40 ÷ 15-1 + ? = 50
(6.013 – 20.04) = ? + 9.98% of 5399.98
236.23-653.23+696.23=?
√256 * 3 – 15% of 300 + ? = 150% of 160
3 √8 × √36 × 13 = ? × √169
75% of 65% of 7/5 of 2420 = ?
Determine the value of ‘x’ if x% of 500 plus {1250 ÷ x of 10} × 5 equals 130
55% of ? = 45 + 20 × 6
What will come in the place of question mark (?) in the given expression?
(125 × 64) ÷ (8 × 5) + (12.5)² – (144 ÷ 3) = ?
...(1225/25) - (192/96) + (50/5) = ?
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