Question
Train βXβ is 360 metres long and takes 18 seconds to
pass a standing man. Speed of train βYβ is 25 m/sec. If both trains are moving towards each other and take 16 seconds to cross completely, what is the length of train βYβ?Solution
ATQ,
Speed of train βXβ = (360/18) = 20 m/sec So, relative speed of train βXβ with respect to train βYβ (moving towards each other) = 20 + 25 = 45 m/sec Let the length of train βYβ = βxβ metres Distance covered together in 16 seconds = (360 + x) metres Or, 16 Γ 45 = 360 + x Or, 720 = 360 + x Or, x = 720 β 360 = 360 So, length of train βYβ = 360 metres
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