Question
Train ‘X’ is 360 metres long and takes 18 seconds to
pass a standing man. Speed of train ‘Y’ is 25 m/sec. If both trains are moving towards each other and take 16 seconds to cross completely, what is the length of train ‘Y’?Solution
ATQ,
Speed of train ‘X’ = (360/18) = 20 m/sec So, relative speed of train ‘X’ with respect to train ‘Y’ (moving towards each other) = 20 + 25 = 45 m/sec Let the length of train ‘Y’ = ‘x’ metres Distance covered together in 16 seconds = (360 + x) metres Or, 16 × 45 = 360 + x Or, 720 = 360 + x Or, x = 720 – 360 = 360 So, length of train ‘Y’ = 360 metres
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