Question
Two trains started from stations ‘A’ and ‘B’ at
same time and started travelling towards each other at speeds of 45 km/hr and 30 km/hr, respectively. At the time of their meeting, the faster train has travelled 117 km more than the slower train. Find the distance between the stations ‘A and ‘B’.Solution
Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 117’ km ATQ, (x/30) = {(x + 117)/45} Or, 45x = 30x + 3510 Or, 15x = 3510 So, x = 234 Total distance between station ‘A’ and station ‘B’ = (234 + 234 + 117) = 585 km
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