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Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 117’ km ATQ, (x/30) = {(x + 117)/45} Or, 45x = 30x + 3510 Or, 15x = 3510 So, x = 234 Total distance between station ‘A’ and station ‘B’ = (234 + 234 + 117) = 585 km
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