Question
'A' alone can do some work in 10 days, 'B' alone can do
the same work in 15 days. If they work on alternate days, starting with 'B', then the work will be finished in:Solution
Solution Let the total work be 30 units {LCM (10 and 15)} So, efficiency of 'A' = 30 ÷ 10 = 3 units/day And efficiency of 'B' = 30 ÷ 15 = 2 units/day Work done in every 2 days (B + A) = 2 + 3 = 5 units So, work done in 12 days by 'A' and 'B' = (12 ÷ 2) x 5 = 30 units Total time taken = 12 days
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