Question
A can complete a work in 12 days and B can complete the
same work in 18 days. They work together for 4 days and then B leaves. In how many more days will A finish the remaining work?Solution
A’s 1-day work = 1/12 B’s 1-day work = 1/18 (A + B)’s 1-day work = 1/12 + 1/18 = (3 + 2) / 36 = 5/36 Work done in 4 days = 4 × 5/36 = 20/36 = 5/9 Remaining work = 1 − 5/9 = 4/9 Time taken by A to finish 4/9 work = (4/9) ÷ (1/12) = (4/9) × 12 = 48/9 = 16/3 days 16/3 days = 5⅓ days
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