Question
A alone can complete a work in 18 days and B alone can
complete it in 27 days. They work together for 6 days and then B leaves. In how many more days will A finish the remaining work?Solution
A’s 1-day work = 1/18 B’s 1-day work = 1/27 (A + B)’s 1-day work = 1/18 + 1/27 = (3 + 2)/54 = 5/54 Work done in 6 days = 6 × 5/54 = 30/54 = 5/9 Remaining work = 1 − 5/9 = 4/9 Time taken by A to do 4/9 work = (4/9) ÷ (1/18) = (4/9) × 18 = 8 days
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