Question
'P' and 'Q' together can complete the work in 12 days.
'Q' alone can complete the work in 20 days. If R is 25% more efficient than P, find the time taken by 'R' alone to finish the work.Solution
Let the total work be 120 units Combined efficiency of 'P' and 'Q' = (120/12) = 10 units/day Efficiency of 'Q' alone = (120/20) = 6 units/day Efficiency of 'P' alone = 10 - 6 = 4 units/day Efficiency of 'R' = 4 X (5/4) = 5 units/day Time taken by 'R' alone to finish the work = 120 ÷ 5 = 24 days
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