Question
A and B together can do a piece of work in 9 days. A
alone can do it in 15 days. In how many days can B alone do it?Solution
A’s 1-day work = 1/15 (A + B)’s 1-day work = 1/9 So B’s 1-day work = 1/9 − 1/15 LCM(9,15) = 45 1/9 = 5/45 1/15 = 3/45 Thus B’s 1-day work = (5 − 3)/45 = 2/45 Time for B alone = 1 ÷ (2/45) = 45/2 = 22.5 days
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