Question
βCβ is 20% less productive compared to βBβ, who
is 25% more productive than βAβ. Together, they finish a job in 40 days. After βAβ and βBβ have worked for 30 days, they stop. How long will βCβ take to finish the remaining work alone?Solution
Let efficiency of βBβ is βxβ units per day
Efficiency of βCβ = 0.80 Γ x = 0.8x units per day
Efficiency of βAβ = x / 1.25 = 0.8x units per day
Total work = (x + 0.8x + 0.8x) Γ 40 = 104x units
Work done by βAβ and βBβ in 30 days = (x + 0.8x) Γ 30 = 54x units
Remaining work = 104x β 54x = 50x units
Desired time = 50x / 0.8x = 62.5 days
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