Question
If βPβ can complete a task in 24 days and βPβ
with βQβ together can finish it in 15 days, then how many days will βQβ take to complete the work alone?Solution
Let the total work = 120 units {LCM (24 and 15)} Efficiency of βPβ = (120/24) = 5 units/day Efficiency of βPβ and βQβ together = (120/15) = 8 units/day Efficiency of βQβ = (8 β 5) = 3 units/day Time taken by βQβ to finish the work alone = (120/3) = 40 days
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