Question
Individually, X, Y and Z can finish a job in 15 days, 20
days, and 24 days respectively. How many days will they take to complete the job working together?Solution
ATQ,
Let the total work be 120 units (LCM of 15, 20 and 24)
Efficiency of 'X' = (120 ÷ 15) = 8 units/day
Efficiency of 'Y' = (120 ÷ 20) = 6 units/day
Efficiency of 'Z' = (120 ÷ 24) = 5 units/day
Required time = 120 ÷ (8 + 6 + 5) = (120 ÷ 19) = 6(6/19) days
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