Question
A alone can complete a piece of work in 12 days and B alone can complete it in 18 days. If they work together, in how many days will they complete the work?
Solution
A’s 1-day work = 1/12 B’s 1-day work = 1/18 Together, 1-day work = 1/12 + 1/18 LCM of 12 and 18 = 36 1/12 = 3/36, 1/18 = 2/36 So together = (3 + 2)/36 = 5/36 Time to complete work = 1 ÷ (5/36) = 36/5 = 7.2 days
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