Three workers A, B and C can finish a job in 10 days, 12 days and 15 days respectively. If the total wages paid to them for completing the work together is Rs. 4500, then by how much is C’s wage less than A’s wage?

ATQ, Efficiency is inversely proportional to time. A can complete the work in 10 days. B can complete the work in 12 days. C can complete the work in 15 days. Their efficiencies will be: A : B : C = 1/10 : 1/12 : 1/15 Take LCM of 10, 12 and 15. LCM = 60 Now multiply each fraction by 60. A’s efficiency = 60/10 = 6 B’s efficiency = 60/12 = 5 C’s efficiency = 60/15 = 4 So, wage ratio of A, B and C = 6 : 5 : 4 Total ratio units = 6 + 5 + 4 = 15 Total wage = Rs. 4500 Value of 1 unit = 4500/15 = Rs. 300 A’s wage = 6 × 300 = Rs. 1800 C’s wage = 4 × 300 = Rs. 1200 Required difference = 1800 − 1200 = Rs. 600