Question
Akhil and Nikhil together can complete a work in 12 days
while Nikhil alone takes 18 days to complete 25% of the work. If the efficiency of Sachin is 20% more than that of Akhil, then find the time taken by Sachin alone to complete the whole work.Solution
Time taken by Nikhil to complete the whole work alone = 18/0.25 = 72 days Let the total work = 72 units Efficiency of (Akhil + Nikhil) = 72/12 = 6 units/day Efficiency of Nikhil = 72/72 = 1 units/day Efficiency of Akhil = 6 - 1 = 5 units/day Therefore efficiency of Sachin = 1.20 x 5 = 6 units/day Time taken by Sachin to complete the whole work alone = 72/6 = 12 days
More Time and work Questions
- What will come in place of (?), in the given expression.
(28 × 4) + (96 ÷ 4) – 25 = ? - What will be come in place of (?) in the given expressions.
45% of 640 + 35% of 320 = ? 3% of 3000 x ?% of 2000 = 3600
25% of 400 + 3 × 102 = ?2
4567.89 - 567.89 - 678.89 = ?
36% of 250 + 26 ÷ 2 × ? = 207
- What will come in the place of question mark (?) in the given expression?
?² = 28% of 35% of 4500 What will come in place of the question mark (?) in the following questions?
55.55% of 30000 – 1111 = ? × 1111
? + 156 ÷ 3 × 7 = 35% of 400 + (13)2
