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    Question

    A can complete a work in 18 hours while B can complete

    it in 12 hours. If C is 80% more efficient than A and B together, then find the time taken by C alone to complete the work.
    A 4 hrs Correct Answer Incorrect Answer
    B 6.4 hrs Correct Answer Incorrect Answer
    C 7.5 hrs Correct Answer Incorrect Answer
    D 10 hrs Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ, Total work = LCM of (18 and 12) = 36 units
    Work by A in one hour = 36 ÷ 18 = 2 units
    Work by B in one hour = 36 ÷ 12 = 3 units
    Work by A and B together = 2 + 3 = 5 units
    C is 80% more efficient → C’s work = 5 + (80% of 5) = 5 + 4 = 9 units
    Time taken by C = 36 ÷ 9 = 4 hours

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