Question
'A' and 'B' together can complete the work in 15 days.
'B' alone can complete the work in 30 days. If C is 50% more efficient than A, find the time taken by 'C' alone to finish the work.Solution
Let the total work be 120 units Combined efficiency of 'A' and 'B' = (120/15) = 8 units/day Efficiency of 'B' alone = (120/30) = 4 units/day Efficiency of 'A' alone = 8 - 4 = 4 units/day Efficiency of 'C' = 4 X (3/2) = 6 units/day Time taken by 'C' alone to finish the work = 120 ÷ 6 = 20 days
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