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Let total work = 60 units (LCM of 10 and 12) Efficiency of ‘A’ = (60/10) = 6 units/day Efficiency of ‘B’ = (60/12) = 5 units/day Combined efficiency of ‘A’, ‘B’ and ‘C’ = (60/4) = 15 units/day Efficiency of ‘C’ = 15 – (6 + 5) = 4 units/day Required time taken = (60/4) = 15 days