New Click here to Enroll for SIDBI MSME Expert Classes by Experts

    Register

    Question

    Three workers P1, P2 and P3 got work from the

    contractor. In 30 days, ‘P1’ completed 30% of work. ‘P2’ is 20% less efficient than ‘P1’ but takes 5 days less than ‘P3’ to complete the work alone. Find the time taken by all three together to complete 33.4% of work.
    A 17 Correct Answer Incorrect Answer
    B 16 Correct Answer Incorrect Answer
    C 13 Correct Answer Incorrect Answer
    D 12.4 Correct Answer Incorrect Answer
    E 10 Correct Answer Incorrect Answer

    Solution

    Time taken by ‘P1’ to complete the work = 30/0.3 = 100 days
    Time taken by ‘P2’ to complete the work = 100/0.8 = 125 days
    Time taken by ‘P3’ to complete the work = 125 + 5 = 130 days
    Let the total work = 6500 units (LCM of 100, 125 and 130)
    Efficiency of ‘P1’ = 6500/100 = 65 units/day
    Efficiency of ‘P2’ = 6500/125 = 52 units/day
    Efficiency of ‘P3’ = 6500/130 = 50 units/day
    Required time taken = (0.334 × 6500)/167 = 13 days

    Practice Next