Question
C is 50% more efficient than D and can complete a task in
18 days. C and D work together for 6 days, after which D leaves. In how many more days will C finish the rest of the task?Solution
ATQ,
Time taken by D to complete the work = 1.5 × 18 = 27 days
Let the total work be 108 units
Efficiency of C = 108/18 = 6 units/day
Efficiency of D = 108/27 = 4 units/day
Work completed in 6 days = (6 + 4) × 6 = 60 units
Remaining work = 108 - 60 = 48 units
Therefore, x = 48 / 6 = 8 days
Simplify the following expression:
Simplify:

6612 ÷ 19 - ?% of 240 = -2196
- Determine the final value of this expression:
(1/5) of {5⁴ - 24 × 14 + 12 × 18 - 10.5 of 10²} 215 + 378 – 23 + 15 - 27 = ? + 3² + 16²
[(36 × 15 ÷ 96 + 19 ÷ 8) × 38] = ?% of 608
(506 ÷ 22 + 9 × 3) × ? = 900 ÷ 9
- What will come in the place of question mark (?) in the given expression?
(198/13) X (52/11) - ? ÷ 5 = 13 + 68 ÷ 4 1/6+ 999*53/54 ×9 = ?
- Find the value of the expression:
40 + 5 – 7 × [16 + 9 – 3 × (27 – 13)]