Question
Workers A and B can finish a task in 30 days when
working together. They worked for 18 days, and then C completed the rest of the task alone in 12 days. How many days will C alone take to finish 75% of the work?Solution
ATQ,
Fraction of work done by A and B = 18 / 30 = 3/5
Fraction of work done by C = 1 - 3/5 = 2/5
So, number of days taken by C alone to complete the entire work = 12 ÷ (2/5) = 30 days
So, time taken by C to complete 75% of the work = 30 × 0.75 = 22.5 days
0 2 10 24 68 120
...150 160 140 ? 130 180
...9256 6844 4888 3350 2152 1276
...130 136 148 166 ? 232
36, 49, 23, 62, ?, 75
Given below are two number series I and II where each series has a wrong (odd one out) number. The number that will actually come in place of the wrong ...
63 189 315 378 567 693
...4, 17, 62, 317, ?, 13267
34 35 44 69 118 ?
2 3.5 11.5 44 192.5 988
9 a...
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