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ATQ,
Let efficiency of a boy and a girl is ‘M’ units per day and ‘W’ units per day respectively. Total task = 10 × 12 × W = 120W units And, 10M = 12W Or, 5M = 6W Efficiency of 5 boys and 2 girls = 5M + 2W = 6W + 2W = 8W units per day Desired time = 120W/8W = 15 days
(? × 3)2 - 85 = 115 × 5 + 69
25% of 250 + 32% of 200 = ? ÷ √ 16
√729 × 5 + 270 - 3 ÷ ∛27 + 4 × ? = 484
Find the value of 16 x [(8 - 5) of 12 ÷ 4].
26 2 – 13% of 400 + (529 ÷ 23 2 ) = ? 2
15.8% of 9000 + 20.4% of 7500 = 30% of ?
(165 × 12) ÷ 45 + 110 = ? × 2
25.6% of 250 + √? = 119