Question
Worker 'A' can complete the entire task in 35 hours, and Worker 'B' can complete it in 40 hours, when working individually. If both 'A' and 'B' work together, how much time will it take for them to finish 60% of the task?
Solution
Let the total work = L.C.M of 35 and 40 = 280 units Then, efficiency of 'A' = 280 ÷ 35 = 8 units/hour Efficiency of 'B' = 280 ÷ 40 = 7 units/hour 60% of the work = 280 X 0.6 = 168 units Time taken by 'A' and 'B' working together to complete 60% of the work = 168 ÷ (7 + 8) = 11.2 hours
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