Question
Arjun is 50% less efficient than the combined efficiency
of Bheem and Cherry. If Bheem can complete a task in 12 days and Cherry in 20 days, determine the time required for all three of them working together to complete the task.Solution
ATQ, Let, total work = LCM of (15 and 12) = 60 units Efficiency of ‘Bheem’ = 60/12 = 5 units/day Efficiency of ‘Cherry’ = 60/20 = 3 units/day Efficiency of ‘Arjun’ = (3 + 5) × 0.5 = 4 units/day Combined efficiency of all 3 of them = (3 + 5 + 4) = 12 units/day Required time taken to complete the work = (60/12) = 5 days
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