Question
A and B together can finish a task in 35 days. If B is
40% more efficient than A, how many days will it take for B alone to complete the task?Solution
Let the amount of work done by A alone in one day be ‘x’ units So the amount of work done by B alone in one day = 1.4x units So the total work = 35 × (x + 1.4x) = 84x units Time taken by B alone to complete the work = 84x/1.4x = 60 days
31% of 3300 +659 = ?
?= √(4 × ∛(16 × √(4 × ∛(16 ×…… ∝)) ) )
60% of 500 + (729) 1/3 - ? = 72
∛857375 + ∛91125 = ? + √6889
1365 ÷ 15 + (? ÷ 5) = 62 × 3.5
Find the Value of
x= √(4 × ∛(16 × √(4 × ∛(16 ×…… ∝)) ) )
?2 = √20.25 × 10 + √16 + 32
36.76 + 2894.713 + 34965.11 =?
(2 ÷ 3) × (4 ÷ 12) × (? ÷ 10) × 45 × (1 ÷ 5) = (? ÷ 6) + (2 ÷ 5)