P, Q & R can finish a work in 10 days, 15 days, and 20 days, respectively, working alone. P and Q work on the first day, P and R work on the second day, P and Q work on the third day, and so on till the work is completed. In how many days the work will be completed?
Then ATQ- First day - P + Q =6+4 =10unit second day-P + R=6+3 =9unit third day P+Q=6+4=10unit total work of three days =10+9+10 =29unit so 58units completed of total work = 3×2 =6days remaining work =60-58 =2 unit so, the remaining work will be completed by P+R = 2/9days Total days = 6+2/9 =56/9days
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