Anita started working and left after 3 days and aftere that Binita started the rest work and finished it in another 5 days. Had Anita left the work after working for 4 days and then Binita started the rest work, it would have been finished in another 2 days. In how many days can each of them alone finish the whole work?
ATQ, (Anita = A and Binita = B) Let Anita finish the work in 'x' days and B in 'y' days Then, (3/x) + (5/y) = 1 Let (1/x) = A, and (1/y) = B then equations can be followed as- 3A + 5B = 1.......(1) 4A + 2B = 1.......(1) Solving both equations we get B = (1/14) days (1/y) = (1/14) Now, 3A + 5B = 1 3A + (5/14) = 1 A = 9/(14 × 3)= (3/14)days therefore B = 14 days and A = (14/3)days
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