Question
'A' and 'B' can do a piece of work together in 30 days.
They worked together for 18 days, and then left the work. The remaining job was finished by 'C' alone in 12 days. How many days would 'C' alone take to finish 72% of the whole work?Solution
ATQ,
Fraction of work done by 'A' and 'B' = 18 / 30 = 3/5 Fraction of work done by 'C' = 1 - 3/5 = 2/5 So, number of days taken by 'C' alone to complete the entire work = 12 ÷ (2/5) = 30 days So, time taken by 'C' to complete 72% of the work = 30 × 0.72 = 21.6 days
Statements: N > U < I ≤ R < D < A; K ≥ O = G > X = E > A
Conclusions:
I. R < E
II. K > D
III. U ≥ X
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