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Let the total work be 132 units. {LCM (22 and 12)} So, efficiency of ‘A’ = (132/22) = 6 units/day So, efficiency of ‘B’ = (6 x 0.5) = 3 unit/day Efficiency of ‘B’ and ‘C’ together = (132/12) = 11 units/day So, efficiency of ‘C’ = 11 – 3 = 8 units/day So, time taken by ‘C’ to finish the work alone = (132/8) = 16.5 days
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