Question
P and Q can complete a work in 36 days and 54 days,
respectively. P, Q and R together can complete the work in 18 days. If R get a total wage of Rs. 5940 to complete the work alone, then find the per day wage of R.Solution
Let the total work be LCM of (36, 54 and 18) = 108 units Number of units of work done by P alone in one day = 108/36 = 3 units Number of units of work done by Q alone in one day = 108/54 = 2 units Number of units of work done by P, Q and R together in one day = 108/18 = 6 units Number of units of work done by R alone in one day = 6 – 3 – 2 = 1 unit So, time taken by R alone to complete the work = 108/1 = 108 days So, per day wage of R = 5940/108 = Rs. 55
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II. 6y2 - 35y + 49 = 0
I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
I. 3p² + 13p + 14 = 0
II. 8q² + 26q + 21 = 0
I). 5p2 - p - 4 = 0
II). q2 - 12q + 27 = 0
I. 5x² - 28x + 39 = 0
II. 2y² - 13y + 20 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
I. 2x2 – 5x - 12 = 0
II. y2 – 11y + 30 = 0
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
I. x2 + 24x + 143 = 0
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I). p2 = 81
II). q2 - 9q + 14 = 0