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Total work = Number of days×1 day’s work (efficiency) Total work = LCM (15, 18) = 90 unit 1 day’s work of A = 90/15 = 6 unit 1 day’s work of B = 90/18 = 5 unit 1 day’s work of (A + B) = 6 + 5 = 11 unit Now, 5 day’s work of (A + B) together = 5× 11 = 55 unit Remaining work = 90 – 55 = 35 Remaining work completed by B = 35/5 = 7 days
192.251 + 326.233 + 125.021 + 19.273 = ?
25 × 5 - ?% of 150 = 102 - 2
√324 + √484 + 63 = ?2
(342 – 20% of 5280) = ? ÷ 3
3(2/5) + 6(1/3) + 3(2/5) + 11(2/3) =?
175 + 24% of 450 = 350 + ?
Simplify the following expression:
1 + 1 + 1/2+ 1/3 + 1/6 + 1/4 is equal to ____
464 + 181 +? = (154 × 25) - (15) 2
(√ 1444 ÷ 5) × 3.25 = ?