Question
'A' is 40% less productive compared to 'B', who is 25%
more productive than 'C'. Together, they can finish a task in 45 days. After 'B' and 'C' have collaborated on the task for 40 days, they stop working. How long will it take for 'A' to finish the remaining part of the task by himself?Solution
Let efficiency of βBβ is βxβ units per day Efficiency of βAβ = 0.60 Γ x = 0.6x units per day Efficiency of βCβ = x/1.25 = 0.8x units per day Total amount of work = (x + 0.6x + 0.8x) Γ 45 = 108x units Amount of work completed by βBβ and βCβ together in 40 days = 1.8x Γ 40 = 72x units Remaining work = 108x β 72x = 36x units Desired time = 36x/0.6x = 60 days
[1.45 X 1.45 X 1.45 + 0.55 X 0.55 X 0.55 + 4.785] = ?
[(82 × 162)/12] - 28 = ?
1299.999 Γ· 325.018 Γ 24.996 = ?
Find the value of 5342.5 +543.45+54.345 +5.4345+0.54345.
(?) x 3 + 68 = β9025
16 of 25 - 12 of 15 = ? of 5 of 11Β
35% of 500 × 22% of ? = 847
36 Γ 15 + 20% 1250 = ? + 296
What is (0.08% of 0.008% of 8)1/9 ?