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Let the efficiency of 'B' be '4y' units/day So, efficiency of 'A' = 0.75 X 4y = '3y' units/day And, efficiency of 'C' = 1.25 X 4y = '5y' units/day Work done by 'A' and 'B' in 10 days = (3y + 4y) X 10 = '70y' units Work done by 'C' = 5y X 10 = '50y' units So, total work = 70y + 50y = '120y' Therefore, required time = (0.8 X 120y) ÷ (3y + 5y) = (96/8) = 12 days
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