I. 2y2 - 37y + 143 = 0 2y2 - 11y - 26 y + 143 = 0 y (2 y – 11) – 13 (2 y – 11) = 0 (y – 13) (2 y – 11) = 0 y = 13, 11/2 II. 2x2 + 15x – 143 = 0 2x2 + 26x - 11 x – 143 = 0 2 x(x + 13) – 11(x + 13) = 0 (2 x – 11) (x + 13) = 0 x = - 13, 11/2 Hence, x ≤y
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