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    Question

    Solve the quadratic equations and determine the

    relation between x and y: Equation 1: 41x² - 191x + 150 = 0 Equation 2: 43y² - 191y + 148 = 0
    A x > y Correct Answer Incorrect Answer
    B x ≥ y Correct Answer Incorrect Answer
    C x < y Correct Answer Incorrect Answer
    D x ≤ y Correct Answer Incorrect Answer
    E x = y or no relation Correct Answer Incorrect Answer

    Solution

    From Equation 1: 41x² - 191x + 150 = 0 Factorizing: (41x - 150)(x - 1) = 0 So, x = 150/41 or x = 1. From Equation 2:          43y² - 191y + 148 = 0 Factorizing: (43y - 148)(y - 1) = 0 So, y = 148/43 or y = 1. Comparing x and y: x = 150/41, y = 148/43, x > y x = 150/41, y = 1, x > y x = 1, y = 148/43, x < y x = 1, y = 1, x = y Correct option : E) x = y or no relation

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