Question
I. √(74x-250 )– x=15 II. √(3y²-37y+18)+
2y=18 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answerSolution
I. √(74x-250 )– x=15 √(74x-250 )=15+x On squaring both sides, we get 74x-250=225+x²+30x x²-44x+475=0 x²-25x-19x+475=0 x (x-25)- 19 (x-25)= 0 (x-19)(x-25)= 0 x=19,25 II. √(3y²-37y+18)+ 2y=18 √(3y²-37y+18)=18-2y On squaring both the sides, we get 3y²-37y+18=324+4y²-72y y²-35y+306=0 y²-17y-18y+306=0 y(y-17)- 18(y-17)= 0 (y-17)(y-18)= 0 y=17,18 Hence, x>y
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