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    Question

    I. √(74x-250 )– x=15 II. √(3y²-37y+18)+

    2y=18 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer 
    A If x ≥y Correct Answer Incorrect Answer
    B If x ≤y Correct Answer Incorrect Answer
    C If x>y Correct Answer Incorrect Answer
    D If x Correct Answer Incorrect Answer
    E If x=y or relationship between x and y cannot be established Correct Answer Incorrect Answer

    Solution

    I. √(74x-250 )– x=15  √(74x-250 )=15+x On squaring both sides, we get 74x-250=225+x²+30x  x²-44x+475=0  x²-25x-19x+475=0  x (x-25)- 19 (x-25)= 0  (x-19)(x-25)= 0  x=19,25  II. √(3y²-37y+18)+ 2y=18 √(3y²-37y+18)=18-2y  On squaring both the sides, we get 3y²-37y+18=324+4y²-72y  y²-35y+306=0  y²-17y-18y+306=0  y(y-17)- 18(y-17)= 0  (y-17)(y-18)= 0  y=17,18  Hence, x>y

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