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Question

In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer 

I. √(74x-250 )– x=15

II. √(3y²-37y+18)+ 2y=18

A If x ≥y Correct Answer Incorrect Answer
B If x ≤y Correct Answer Incorrect Answer
C If x>y Correct Answer Incorrect Answer
D If x Correct Answer Incorrect Answer
E If x=y or relationship between x and y cannot be established Correct Answer Incorrect Answer

Solution

I. √(74x-250 )– x=15  √(74x-250 )=15+x On squaring both sides, we get 74x-250=225+x²+30x  x²-44x+475=0  x²-25x-19x+475=0  x (x-25)- 19 (x-25)= 0  (x-19)(x-25)= 0  x=19,25  II. √(3y²-37y+18)+ 2y=18 √(3y²-37y+18)=18-2y  On squaring both the sides, we get 3y²-37y+18=324+4y²-72y  y²-35y+306=0  y²-17y-18y+306=0  y(y-17)- 18(y-17)= 0  (y-17)(y-18)= 0  y=17,18  Hence, x>y

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