Question
I. √(74x-250 )– x=15 II. √(3y²-37y+18)+
2y=18 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answerÂSolution
I. √(74x-250 )– x=15  √(74x-250 )=15+x On squaring both sides, we get 74x-250=225+x²+30x x²-44x+475=0 x²-25x-19x+475=0 x (x-25)- 19 (x-25)= 0 (x-19)(x-25)= 0 x=19,25 II. √(3y²-37y+18)+ 2y=18 √(3y²-37y+18)=18-2y On squaring both the sides, we get 3y²-37y+18=324+4y²-72y y²-35y+306=0 y²-17y-18y+306=0 y(y-17)- 18(y-17)= 0 (y-17)(y-18)= 0 y=17,18 Hence, x>y
(43)² - (28)² + (32)² = ?% of 2500
18 + 28 ÷ 4 - 14 = ? - 35
...2/5 of 3/4 of 7/9 of 7200 = ?
What will come in the place of question mark (?) in the given expression?
? = (20 × 62 – 342 )
Find the value of 325 × 5 + 31 × 21 – 22 × (63 − 52).
168Â Â Â Â Â 163Â Â Â Â Â Â 153Â Â Â Â Â Â 138Â Â Â Â Â 118Â Â Â Â Â ?
...26 2 – 13% of 400 + (529 ÷ 23 2 ) = ? 2Â
(12% of 1250 + 85% of 400) x 10 = ?2
Find the value of the given expression.
[76 – {90 ÷ 5 × (24 – 36 ÷ 3) ÷ 3}]
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