Question
I. x2 β 3(x + 5) = -11 II.
y2 β 4(y + 2) = -2y In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer:Solution
I. x2Β β 3(x + 5) = -11 => x2Β β 3x - 15 = -11 => x2Β β 3x - 4 = 0 => x2Β β 4x + x β 4 = 0 => x(x β 4) + 1(x β 4) = 0 => (x β 4) (x + 1) = 0 => x = 4, -1 II. y2Β β 4(y + 2) = -2y => y2Β β 4y β 8 = -2y => y2Β β 2y β 8 = 0 => y2Β β 4y + 2y - 8 = 0 => y(y β 4) + 2(y β 4) = 0 => (y β 4) (y + 2) = 0 => y = 4, -2 Hence, the relationship between x and y cannot be established.
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