Answer-I. x2 – 3(x + 5) = -11 II. y2 – 4(y + 2) = -2y

I. x2 3x 5 -11 x2 3x - 15 -11 x2 3x - 4 0 x2 4x x 4 0 xx 4 1x 4 0 x 4 x 1 0 x 4, -1 II. y2 4y 2 -2y y2 4y 8 -2y y2 2y 8 0 y2 4y 2y - 8 0 yy 4 2y 4 0 y 4 y 2 0 y 4, -2 Hence, the relationship between x and y cannot be established.

Question

I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y

In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer:

A if x > y

B if x ≥ y

C if x < y

D if x ≤ y

E if x = y or the relationship cannot be established

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I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y

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I. x2 – 3(x + 5) = -11II. y2 – 4(y + 2) = -2y

Detailed Solution

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I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y