New Click here to Enroll in NaBFID Analyst Intro Class on May 6

    Question

    In each of these questions two equations numbered I and II are given. You have to solve both the equations and give answer, if – 

    I. 3p² - 14p + 15 = 0 II. 15q²  - 34q + 15 =

    0
    A p =q or relationship cannot be established between p and q. Correct Answer Incorrect Answer
    B p > q Correct Answer Incorrect Answer
    C p < q Correct Answer Incorrect Answer
    D p ≥ q Correct Answer Incorrect Answer

    Solution

    I. 3p² - 14p + 15 = 0 3p²  - 9p  - 5p + 15 = 0 ⟹3 p(p - 3)  - 5(p  - 3) = 0      ⟹ (p  - 3) (3p  - 5)= 0 ⟹ p = 3,    5/3 II. 15q²  - 34q + 15 = 0 ⟹15q²  25q  - 9q + 15 =0 ⟹5q(3q  - 5) - 3(3q - 5)= 0 ⟹ (3q  - 5) (5q - 3)= 0 ⟹ q =  5/3 ,  3/5 ∴p≥q

    Practice Next

    Relevant for Exams: