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    Question

    The following question contains two equations as I and

    II.You have to solve both equations and determine the relationship between them. I). a² - 12a - 108 = 0 II). b² + 28b + 132 = 0
    A a > b Correct Answer Incorrect Answer
    B a < b Correct Answer Incorrect Answer
    C a ≥ b Correct Answer Incorrect Answer
    D a ≤ b Correct Answer Incorrect Answer
    E a = b or the relationship between x and y cannot be determined. Correct Answer Incorrect Answer

    Solution

    I. a² - 12a -108 = 0 a² - 18a + 6a – 108 = 0 a (a – 18) +6 (a-18) = 0 (a + 6)(a -18) = 0 a = -6, 18 II. b² + 28b +132 = 0 b² + 6b +22b +132 = 0 b (b+6) + 22 (b+6) = 0 (b +22) (b+6) = 0 b = -6, -22 Therefore a ≥ b.

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