Question
A mixture contains 80 ml water and rest ‘x’ ml milk.
When 0.25x ml of water is added to the mixture, the quantity of water becomes 1/3rd of the mixture. Find the value of ‘x’.Solution
According to the question,
Quantity of water after addition of 0.25x ml water = (80 + 0.25x)
Total quantity of the mixture = 80 + 0.25x + x = (80 + 1.25x)
Therefore,
(1/3)(80 + 1.25x) = (80 + 0.25x)
Or, 80 + 1.25x = 240 + 0.75x
Or, 0.5x = 160
Or, x = 320
40.5 ÷ [4/5 of (32 + 18) - 29/2] = ? ÷ 102
121/? = ?/144
300% of (3341 – 471) = ? × (√4225/195)
Find the simplified value of the given expression
- Simplify:
13 X √? + 256 ÷ 4 = 30% of 900 - 50
What will come in the place of question mark (?) in the given expression?
? = 12.5% of 25% of 20% of 1280 + 1248
What will come in the place of question mark (?) in the given expression?
{180 + (2250/15)} ÷ 11 = ?2 + 14
What will come in place of the question mark (?) in the following expression?
40% of 150 – ?% of 80 = 25% of 400
What will come in the place of question mark (?) in the given expression?
(√1089 + √484) X 5 + ? = 725
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