Question
My grandmother was 9 times older to me 18 years ago. She
would be 3 times of my age 9 years from now. 9 years ago, what was the ratio of my age to that of my grandmother?Solution
Let my age 18 years ago be x years My grandmother’s age at that time = 9 x years My present age = (x + 18) years My grandmother’s present age = (9 x + 18) years According to question 3(x + 18 + 9) = (9 x + 18 + 9) 3 x + 81 = 9 x + 27 9 x - 3 x = 81 – 27 6 x = 54 x = 9 Now, ratio of ages 9 years ago = (x + 18 -9 )/(9x +18 - 9) = (9 + 18 - 9)/(9 × 9 + 18-9 )=18/90 = 1:5
1519.98 ÷ 50.48 × 15.12 = ? × 4.16
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04
The average marks of 15 candidates were reported as 84. However, it was later discovered that the marks of three candidates were ...
(752.09 - 43.04 x 7.94) ÷ 16.9 = ?
180.25 × 14.995 ÷ √26 = ? × 5.985
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...