Question
The present age of A is 8/5 times to that of his
marriage age. Present age of his brother is 1/2nd of his present age. If A was married 15 years ago then find the present age of his brother.Solution
Let the age of A when he was married be x years. Present age of A = 8x/5 Present age of his brother = (1/2) × (8x/5) = 4x/5 According to Question, => x + 15 = 8/5x => 3/5x = 15 => x = 25 years Present age of his brother = (4/5) × 25 = 20 years
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