The present age of A is 8/5 times to that of his marriage age. Present age of his brother is 1/2nd of his present age. If A was married 15 years ago then find the present age of his brother.
Let the age of A when he was married be x years. Present age of A = 8x/5 Present age of his brother = (1/2)×(8x/5) = 4x/5 According to Question, => x + 15 = 8/5x => 3/5x = 15 => x = 25 years Present age of his brother = (4/5) ×25 = 20 years
I. x2 + 24x + 154 = 0
II. y2 + 27y + 181 = 0
I. x³= ((4)5+ (15)³)/(3)4
II. 8y³=(-13)3÷ √1521+ (3y)³
I. 2x² - 15x + 13 = 0
II. 3y² - 6y + 3 = 0
I. 27x² + 120x + 77 = 0
II. 56y² + 117y + 36 = 0
I. 63x2+ 148x + 77 = 0
II. 21y2+ 89y + 88 = 0
I. p2+ 2p – 8 = 0 II. q2 – 5q + 6 = 0
I. y² + y – 56 = 0
II. 2x² + 11 x – 40 = 0
I. 8y2- 2y - 21 = 0
II. 2x2+ x - 6 = 0
(i) 2x² – 9x + 10 = 0
(ii) 4y² – 12y + 9 = 0
I. 2x² + 15 x - 27 = 0
II. 3 y² + 25 y - 18 = 0
