Question
If 6 is added to each number and then digits of
each number is reversed, what will be the digit sum of the number which will be at the second position if numbers are arranged in ascending order? These questions are based on the following set of numbers: 523 224 347 758 612Solution
523 224 347 758 612 529 230 353 764 618 925 032 353 467 816 032 353 467 816 925 (Arranged in ascending order). Sum = 3 + 5 +3 = 11
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