Question
Two cities M and N are 432 km apart. A bus leaves M at
7:15 a.m. at 48 km/h. Another bus leaves N at 8:45 a.m. towards M at 72 km/h. At what time will they meet?Solution
Time gap = 1.5 hrs → Distance = 48 × 1.5 = 72 km
Remaining = 432 – 72 = 360 km
Relative speed = 120 km/h
Time = 360 / 120 = 3 hours
Meeting time = 8:45 a.m. + 3h = 11:45 a.m.
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